No More Worries!


Our orders are delivered strictly on time without delay

Paper Formatting

  • Double or single-spaced
  • 1-inch margin
  • 12 Font Arial or Times New Roman
  • 300 words per page

No Lateness!

image Our orders are delivered strictly on time without delay

AEW Guarantees

image

  • Free Unlimited revisions
  • Guaranteed Privacy
  • Money Return guarantee
  • Plagiarism Free Writing

Investigating pH in Acid-Base Solutions

1. 10 mL of M HCl solution is mixed with 150 mL of water to make a new HCl solution. What is the pH of the resultant solution? Justify your answer.

2. Let’s prepare an H2SO4 solution by dissolving 4.9 grams of H2SO4 in 100 mL of water.
a. How many H2SO4 molecules are in this solution?
b. What is the molarity of the solution?
c. What is the pH of the solution?
d. What is the pH of the solution if 3.0 grams of NaOH are added to the solution?
Note: Sulfuric acid (H2SO4) is a diprotic acid. The dissociation constant of the first proton (H+) is significantly larger than the second H+ dissociation. So, the pH of such a solution is mainly contributed by the first proton dissociation, while the second proton dissociation will provide some modification to its pH value. If you haven’t learned polyprotic acids yet, consider one H+ dissociation is enough to be awarded full credit.

Sample Answer

 

Investigating pH in Acid-Base Solutions

1. pH of HCl Solution

When 10 mL of 1 M HCl solution is mixed with 150 mL of water, the resultant solution’s pH can be calculated. The dilution equation, (M_1V_1 = M_2V_2), can be applied to determine the final concentration of the HCl solution. By substituting the values, we find that the final concentration is 0.067 M. Since HCl is a strong acid that dissociates completely in water, the concentration of H+ ions is equal to the concentration of HCl. Therefore, the pH of the resultant solution can be calculated as pH = -log[H+], which gives a pH of approximately 1.18.

2. H2SO4 Solution Preparation

a. The number of H2SO4 molecules can be calculated using Avogadro’s number and the molar mass of H2SO4. By dividing the given mass by the molar mass of H2SO4 and then multiplying by Avogadro’s number, we find the number of molecules in the solution.
b. The molarity of the solution is calculated by dividing the moles of H2SO4 by the volume in liters.
c. The pH of the H2SO4 solution can be calculated using the formula pH = -log[H+]. Since sulfuric acid is a diprotic acid, only the dissociation of the first proton contributes significantly to the pH.
d. When 3.0 grams of NaOH are added, a neutralization reaction occurs with H2SO4, producing water and salt. The excess NaOH will affect the pH of the solution, which can be calculated based on the new concentrations of the remaining species.

By following these steps and calculations, a comprehensive understanding of the pH variations in acid-base solutions can be achieved.

 

 

This question has been answered.

Get Answer
PLACE AN ORDER NOW

Compute Cost of Paper

Subject:
Type:
Pages/Words:
Single spaced
approx 275 words per page
Urgency:
Level:
Currency:
Total Cost:

Our Services

image

  • Research Paper Writing
  • Essay Writing
  • Dissertation Writing
  • Thesis Writing

Why Choose Us

image

  • Money Return guarantee
  • Guaranteed Privacy
  • Written by Professionals
  • Paper Written from Scratch
  • Timely Deliveries
  • Free Amendments