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Title: Understanding the Acceleration of a Train
Thesis Statement: By examining the scenario of a train starting from a railway station and achieving a speed of 40 km/h in 10 minutes, we can calculate its acceleration through basic physics principles.
Trains have long been a vital mode of transportation, connecting people and places efficiently. When a train begins its journey from a stationary position and gradually increases its speed, the concept of acceleration comes into play. Acceleration, a fundamental physics concept, describes how an object’s velocity changes over time.
In this scenario, we are presented with a train that starts from rest at a railway station and reaches a speed of 40 km/h in 10 minutes. To determine the train’s acceleration, we can utilize the formula for acceleration:
[Acceleration = \frac{Change in Velocity}{Time Taken}]
Given that the initial velocity (u) of the train is 0 km/h (as it starts from rest) and the final velocity (v) is 40 km/h, the change in velocity (∆v) is:
[\Delta v = v – u]
[\Delta v = 40 km/h – 0 km/h]
[\Delta v = 40 km/h]
Converting the time taken to reach this speed into hours:
[Time = 10 \text{ minutes} = \frac{10}{60} \text{ hours}]
[Time = \frac{1}{6} \text{ hours}]
Now, we can calculate the acceleration of the train:
[Acceleration = \frac{40 \text{ km/h}}{\frac{1}{6} \text{ hours}}]
[Acceleration = 240 \text{ km/h} \times 6]
[Acceleration = 1440 \text{ km/h}^2]
Therefore, the acceleration of the train starting from the railway station is 1440 km/h^2. This value indicates how quickly the train’s velocity is increasing per unit time until it reaches the speed of 40 km/h.
Understanding the concept of acceleration in such scenarios not only helps us comprehend the physics behind motion but also highlights the significance of time, velocity, and change in speed during an object’s journey. Trains, with their intricate mechanics and precise calculations, showcase the application of fundamental physics principles in real-world situations.
