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Sample Answer

 

To calculate the margin of error for the 95% confidence level, we can use the formula:

Margin of Error = Z * (sqrt(p * (1 – p) / n))

Where:

Z* is the z-score corresponding to the desired confidence level (95% in this case), which is 2.576.
p is the proportion of respondents who are against the bond measures, which is 72/1000 = 0.072.
n is the sample size, which is 1000.
Plugging in the values:

Margin of Error = 2.576 * (sqrt(0.072 * (1 – 0.072) / 1000))

Calculating this expression:

Margin of Error = 2.576 * (sqrt(0.072 * 0.928 / 1000))

Margin of Error = 2.576 * (sqrt(0.067296 / 1000))

Margin of Error = 2.576 * (sqrt(0.000067296))

Margin of Error ≈ 2.576 * 0.008206

Margin of Error ≈ 0.0211

Therefore, the margin of error for the 95% confidence level is approximately 0.0211 or 2.11%.

 

 

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